cool-image

byVijay Jogi

// Simplified Swift (iOS) conceptual code for uploading a post func uploadPost(image: UIImage, caption: String) { let url = URL(string: "https://api.instagram.com/v2/posts")! var request = URLRequest(url: url) request.httpMethod = "POST" let postData = [ "userId": "user_12345", "caption": caption, "image_data": image.jpegData(compressionQuality: 0.8)?.base64EncodedString() ] // Code to execute the network request and handle success/error NetworkManager.shared.send(request, with: postData) { result in print("Post successfully uploaded!") }# Simplified Python (Django-style) conceptual backend code from django.db import models from django.http import JsonResponse # 1. Database Model for a Post class Post(models.Model): user_id = models.CharField(max_index=True, max_length=50) image_url = models.URLField() caption = models.TextField() created_at = models.DateTimeField(auto_now_add=True) # 2. API Endpoint View to handle creation def create_post(request): if request.method == 'POST': # Extract data from the mobile request user_id = request.POST.get('userId') caption = request.POST.get('caption') image_file = request.FILES.get('image') # Upload image to Content Delivery Network (CDN) cdn_url = CDNStorage.upload(image_file) # Save reference details in the database post = Post.objects.create( user_id=user_id, image_url=cdn_url, caption=caption ) # Push to Graph Database so followers' feeds are updated FeedManager.push_to_followers(user_id, post.id) return JsonResponse({"status": "success", "post_id": post.id}, status=201) }